anyone good at algebra?

[Jan]

You introduce a new variable y = x^(1/3).

[bryantm3]

so that would leave the equation at y^2 -9y +8, correct?
so y would equal 1 and 8. 1^3 is 1, 8^3 is 512. thanks, that makes a lot more sense. i wonder why the teacher never taught that? maybe i wasn't there that day.